2014 Sacramento Challenger – Doubles
2014 Sacramento Challenger – Doubles
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| Doubles | |
|---|---|
| 2014 Sacramento Challenger | |
| Champions | |
| Runners-up | |
| Final score | 6–3, 6–2 |
John-Patrick Smith and Matt Reid were the defending champions, however they chose not to participate with each other. Smith partners Adam Hubble, whilst Reid partners Jose Statham.
Adam Hubble and John-Patrick Smith won the title by defeating Peter Polansky and Adil Shamasdin 6–3, 6–2 in the final.
Contents
1 Seeds
2 Draw
2.1 Key
3 References
Seeds[edit]
Marcus Daniell /
Artem Sitak (Semifinals)
Peter Polansky /
Adil Shamasdin (Final)
Bradley Klahn /
Tim Smyczek (withdrew)
Sekou Bangoura /
Tennys Sandgren (First round)
Draw[edit]
Key[edit]
- Q = Qualifier
- WC = Wild Card
- LL = Lucky Loser
- Alt = Alternate
- SE = Special Exempt
- PR = Protected Ranking
- w/o = Walkover
- r = Retired
- d = Defaulted
| First round | Quarterfinals | Semifinals | Final | ||||||||||||||||||||||||
| 1 | 6 | 77 | |||||||||||||||||||||||||
| WC | 1 | 64 | 1 | 2 | 78 | [10] | |||||||||||||||||||||
| Q | 3 | 3 | | 6 | 66 | [4] | |||||||||||||||||||||
| | 6 | 6 | 1 | 4 | 77 | [14] | |||||||||||||||||||||
PR/4 | 1 | 4 | PR | 6 | 65 | [16] | |||||||||||||||||||||
| PR | 6 | 6 | PR | 6 | 66 | [10] | |||||||||||||||||||||
| | 3 | 4 | | 4 | 78 | [8] | |||||||||||||||||||||
| | 6 | 6 | PR | 6 | 6 | ||||||||||||||||||||||
| | 5 | 6 | [10] | 2 | 3 | 2 | |||||||||||||||||||||
| WC | 7 | 4 | [2] | | 6 | 4 | [7] | ||||||||||||||||||||
| WC | 7 | 6 | WC | 4 | 6 | [10] | |||||||||||||||||||||
| LL | 5 | 4 | WC | 4 | 2 | ||||||||||||||||||||||
| | 6 | 4 | [8] | 2 | 6 | 6 | |||||||||||||||||||||
| PR | 3 | 6 | [10] | | 2 | 4 | |||||||||||||||||||||
| | 66 | 0 | 2 | 6 | 6 | ||||||||||||||||||||||
| 2 | 77 | 6 | |||||||||||||||||||||||||
References[edit]
- Main Draw
- Qualifying Draw
Categories:
- 2014 ATP Challenger Tour
- 2014 Sacramento Challenger
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